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B
B
C
D
$6x^2y$
$2(x^2-9)$
$10a^2b^2c$
$2a^2$
5bc
$ab^2$
$\frac{x+1}{x^2-1}$
$\frac{x-1}{x²-1}$
$ \frac{1}{x²-1}$
$ \begin{aligned}解:\frac{2}{xy}&=\frac{4}{2xy} \\ \frac{x}{2y}&=\frac{x^2}{2xy} \\ \end{aligned}$
$ \begin{aligned} 解:\frac{5}{-4ab^2}&=-\frac{25a}{20a^2b^2} \\ \frac{4}{5a^2b}&=\frac{16b}{20a^2b^2} \\ \end{aligned}$
$ $
$ \begin{aligned} 解:\frac{x}{a(x-y)}&=\frac{bx}{ab(x-y)} \\ \frac{y}{b(y-x)}&= -\frac{ay}{ab(x-y)} \\ \end{aligned}$
$ \begin{aligned}解:\frac{a}{(x-y)^2}&= \frac{a(x+y)}{(x-y)^2(x+y)} \\ \frac{b}{(x-y)(x+y)}&=\frac{b(x-y)}{(x-y)^2(x+y)} \\ \end{aligned}$
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