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第62页

信息发布者：

$\frac{2}{5}$

$\frac{1}{3}$

$\frac{2}{9}$

$\frac{12}{35}$

$\frac{1}{3}$

$\begin{aligned} 解： x&=\frac 12-\frac 14\\x&=\frac 14\end{aligned}$

$\begin{aligned} 解： x&=1-\frac 35\\x&=\frac 25\end{aligned}$

$\begin{aligned} 解： x&=\frac 56+\frac 12\\x&=\frac 43\end{aligned}$

$\begin{aligned} 解： x&=\frac 25+\frac 47\\x&=\frac {34}{35}\end{aligned}$

$=\frac {7}{8}+\frac {1}{8}+\frac {4}{7}$

$=1+\frac {4}{7}$

$=\frac {11}{7}$

$=(\frac {1}{6}+\frac {1}{6})+(\frac {3}{5}+\frac {2}{5})$

$=\frac {1}{3}+1$

$=\frac {4}{3}$

$=\frac {9}{5}-(\frac {2}{7}+\frac {5}{7})$

$=\frac {9}{5}-1$

$=\frac {4}{5}$

$=(\frac {5}{9}+\frac {4}{9})-(\frac {3}{8}+\frac {3}{8})$

$=1-\frac {6}{8}$

$=\frac {1}{4}$

$=\frac {5}{6}-\frac {1}{4}$

$=\frac {7}{12}$

$=\frac {2}{5}-\frac {2}{5}+\frac {2}{3}$

$=\frac {2}{3}$