解：$(1)f=0.1G=0.1×2.5×10^4\ \text {N}=2.5×10^3\ \text {N}$
$ (2)s_{ }=v_{ } t_{ }={ 10 }\ \text {m/s}×{ \frac {36}{3.6} }\ \text {s}={ 100 }\ \text {m}$
$ W=Fs={ 2.5×10^3 }\ \text{N}×{ 100 }\ \text{m}={ 2.5×10^5 }\ \text{J}$
$ (3)F_{ }=\frac{P_{ }}{v_{ }}=\frac{{ 90×10^3 }\ \text {W}}{{ \frac {90}{3.6} }\ \text {m/s}}={ 3.6×10^3 }\ \text {N}$
$ G_总=10F=3.6×10^4\ \text {N}$
$ G_货=G_总-G=3.6×10^4\ \text {N}-2.5×10^4\ \text {N}=1.1×10^4\ \text {N}$
