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第76页

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$ 解：(1)V_水=\frac {m_水}{ρ_水}=\frac { 9\ \text {kg}}{1.0×10^{3}\ \text {kg/m}^3}= 0.009\ \text {m}^3$

$ (2)V_冰=\frac {m_水}{ρ_冰}=\frac {9\ \text {kg}}{0.9×10^{3}\ \text {kg/m}^3}= 0.01\ \text {m}^3$

$ (3)水结冰后，体积变大，可能会胀破水管$

$ 解：V_铝=\frac {m_铝}{ρ_铝}=\frac {27\ \text {g}}{2.7\ \text {g/cm}^3}=10\ \text {cm}^3$

$ m_液=m_总-m_铝=43\ \text {g}- 27\ \text {g}=16\ \text {g}$

$ V_液=V_球-V_铝=30\ \text {cm}^3-10\ \text {cm}^3=20\ \text {cm}^3$

$ ρ_液=\frac {m_液 }{V_液}=\frac {16\ \text {g}}{ 20\ \text {cm}^3}=0.8\ \text {g/cm}^3$