= $\frac49+\frac59+\frac67$ = $1+\frac67$ = $1\frac67$
= $\frac34+\frac13-\frac56$ = $\frac34-\frac12$ = $\frac14$
= $(\frac5{12}+\frac7{12})+(\frac47+\frac37)$ =1+1 =2
= $\frac23+\frac13-(\frac38+\frac58)$ =1-1 =0
= $(\frac{13}7-\frac67)-(\frac45+\frac15)$ = $1-1$ $=0$
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