$ 解：(1)F=G=mg= 22×10^{3}\ \text {kg}×10\ \text {N/kg}=2.2×10^{5}\ \text {N}$
$ p=\frac {F}{S}=\frac {2.2×10^{5}\ \text {N}}{2×2\ \text {m}^2}=5.5×10^{4}\ \text {Pa}$
$ (2)F_浮=G=2.2×10^{5}\ \text {N}$
$ V_排=\frac {F_浮}{ρ_水g}=\frac {2.2×10^{5}\ \text {N}}{1×10^{3}\ \text {kg/m}^3×10\ \text {N/kg}}=22\ \text {m}^3$
