电子课本网 › 第77页

第77页

信息发布者：

$\frac {8}{21}$

$\frac {35}{36}$

$\frac {4}{5}$

$\frac {2}{7}$

$\frac {5}{7}$

$\frac {3}{20}$

$\begin {aligned}解：x&=\frac {1}{6}+\frac {1}{5}\\x &=\frac {11}{30}\end {aligned}$

$\begin {aligned}解：x&=\frac {11}{9}-1\\x &=\frac {2}{9}\end {aligned}$

=$1+\frac {4}{11}$

$=1 \frac {4}{11}$

=1-1

$\frac {4}{5}$ + $\frac {4}{5}$ + $\frac {3}{8}$=$\frac {79}{40}$ (厘米)

答：它的周长是$\frac {79}{40}$厘米。

$\frac {5}{6}$-$\frac {1}{5}$ -$\frac {1}{5}$=$\frac {13}{30}$ (千克)

答：乙瓶原来有饮料$\frac {13}{30}$千克。

4÷12=$\frac {1}{3}$

5÷9=$\frac {5}{9}$

1- $\frac {1}{3}$ -$\frac {5}{9}$=$\frac {1}{9}$

答：还剩下这瓶果汁的$\frac {1}{9}。$