电子课本网 第82页

第82页

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1
$1\frac{4}{7}$
$\frac{11}{15}$
$1\frac{1}{5}$
$\frac{2}{9}$
$\frac{3}{16}$
$1\frac{1}{6}$
$\frac{2}{3}$
$\begin {aligned}解:x&=\frac {3}{2}-\frac {2}{5}\\x &=\frac {11}{10}\end {aligned}$
$\begin {aligned}解:x&=\frac {3}{8}+\frac {5}{12}\\x &=\frac {19}{24}\end {aligned}$
$\begin {aligned}解:x&=\frac {11}{12}-\frac {3}{5}\\x &=\frac {19}{60}\end {aligned}$
$\begin {aligned}解:x&=\frac {2}{3}-\frac {1}{5}\\x &=\frac {7}{15}\end {aligned}$
$\begin {aligned}解:x&=1-\frac {1}{4}\\x &= \frac {3}{4}\end {aligned}$
$\begin {aligned}解:x&=\frac {2}{3}+\frac {1}{5}-\frac {4}{5}\\x &=\frac {13}{15}-\frac {4}{5}\\x &=\frac {1}{15}\end {aligned}$
​$=\frac {29}{24}+\frac {3}{4}$​
​$=\frac {47}{24}$​
​$=\frac {33}{50}-\frac {1}{5}$​
​$=\frac {23}{50}$​
​$=\frac {29}{24}-\frac {7}{16}$​
​$=\frac {37}{48}$​
​$=\frac {14}{9}-\frac {1}{2}$​
​$=\frac {19}{18}$​
​$=1+\frac {8}{9}$​
​$=1\frac 89$​
​$=(\frac {19}{11}-\frac {8}{11})+\frac {2}{3}$​
​$=1+\frac {2}{3}$​
​$=1\frac 23$​
​$=\frac {13}{12}-1$​
​$=\frac {1}{12}$​
​$=(\frac {6}{13}+\frac {7}{13})-(\frac {3}{7}+\frac {4}{7})$​
​$=1-1$​
​$=0$​