由于$ \frac {1}{6}= \frac {25}{150}，$$ \frac {1}{5}= \frac {30}{150}，$$ \frac {27}{150}= \frac {9}{50}，$
可知$ \frac {1}{6}＜ \frac {9}{50}＜ \frac {1}{5}.$
由于$ \frac {1}{6}= \frac {15}{90}，$$ \frac {1}{5}= \frac {18}{90}，$$ \frac {16}{90}= \frac {8}{45}，$
可知$ \frac {1}{6}＜ \frac {8}{45}＜ \frac {1}{5}.$
由此可知，满足条件的数有$ \frac {8}{45}$
