电子课本网 第106页

第106页

信息发布者:
13
$\frac{1}{12}$
$\frac{1}{8}$
$\frac{1}{4}$
$1-\frac{63}{64}$
0
$\frac{25}{33}$
11
21
$10分钟=\frac{1}{6}小时$
$\frac{5}{7}-\frac{1}{6}+\frac{5}{7}=\frac{53}{42}(小时)$
$答:这名游客上山、下山共用了\frac{53}{42}小时。$
$\frac{11}{12}-(\frac{1}{4}+\frac{1}{4}+\frac{1}{6})=\frac{1}{4}(吨)$
$答:原来乙仓库存粮\frac{1}{4}吨。$
$1-(\frac{1}{2}+\frac{1}{4}+\frac{1}{8} +\frac{1}{16})$
$ \begin{aligned} &=1-(1-\frac{1}{16}) \\ &=\frac{1}{16} \\ \end{aligned}$
$答:还剩总数的\frac{1}{16}。$
$因为[19,5]=95$
$\frac{x}{19}<\frac{4}{5}<\frac{y}{19}$
$可以改写为\frac{5x}{95}<\frac{76}{95}<\frac{5y}{95}$
$5x<76<5y$
$所以x=15,y=16。$
(更多请点击查看作业精灵详解)
$三个分数的分母不可能都比3大,如果有两个$
$分数分别是\frac{1}{2}和\frac{1}{3}$
$那么另一个分数就是$
$1-\frac{1}{2}-\frac{1}{3}=\frac{1}{6}$
$所以\frac{1}{2}+\frac{1}{3}+\frac{1}{6}=1$
$~~~~\frac{1}{2}+\frac{3}{4}+\frac{7}{8}+\frac{15}{16}+\frac{31}{32}+\frac{63}{64}+\frac{127}{128}+\frac{255}{256}$
$= 1-(\frac{1}{2})+(1- \frac{1}{4} )+(1- \frac{1}{8} )+···+ (1-\frac{1}{256})$
$=8-( \frac{1}{2} +\frac{1}{4}+\frac{1}{8}+···+\frac{1}{256})$
$=8-(1-\frac{1}{256} )$
$=8-1+ \frac{1}{256}$
$=7 \frac{1}{256}$
$~~~~\frac{1}{2}+\frac{1}{3}+\frac{2}{3}+\frac{1}{4}+\frac{2}{4}+\frac{3}{4}+\frac{1}{5}+\frac{2}{5}+···+\frac{1}{10}$
$~~~~+\frac{2}{10}+···+\frac{9}{10}$
$=0.5+1+1.5+2+···+4.5$
$=(0.5+4.5)×9÷2$
$=22.5$