电子课本网 第45页

第45页

信息发布者:
解:原式​$=(-2023-\frac {2}{3})+(-2024-\frac {5}{6})+(4304-\frac {1}{2}) $​
​$=[(-2023)+(-20224)+43304]+[(-\frac {2}{3})+(-\frac {5}{6})-\frac {1}{2}]$​
​$=257+(-2)$​
​$=255$​
解:原式​$=-\frac {1}{1×2}-\frac {1}{2×3}-\frac {1}{3×4}-\frac {1}{4×5}-\frac {1}{5×6}- \frac {1}{6×7}$​
​$=-(1-\frac {1}{2})-(\frac {1}{2}- \frac {1}{3})-(\frac {1}{3} -\frac {1}{4})-(\frac {1}{4} -\frac {1}{5})-(\frac {1}{5}-\frac {1}{6})-(\frac {1}{6}-\frac {1}{7})$​
​$=-1+\frac {1}{7}$​
​$=-\frac {6}{7}$​
解:原式​$=(-\frac {6}{5})×(-\frac {2}{3}+\frac {17}{3})$​
​$=-\frac {6}{5}×5$​
​$=-6$​
解:原式​$=(\frac 38-\frac 16+\frac {5}{12})×(-24)$​
​$=\frac 38×(-24)-\frac 16×(-24)+\frac {5}{12}×(-24)$​
​$=-9+4-10$​
​$=-15$​