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B
B
C
C
$\frac{4}{7}$
$1\frac{1}{3}$
$\frac{7}{12}$
2.1
$\frac{2}{21}$
10
24
$\frac{5}{36}$
$=\frac {1}{7} ×\frac {1}{7}+7 ×7$
$=\frac {1}{49}+49$
$=49 \frac {1}{49}$
$=\frac {4}{25} \div (\frac {11}{15} ×\frac {9}{11})$
$=\frac {4}{25} \div \frac {3}{5}$
$=\frac {4}{15}$
$=(\frac {1}{2}+\frac {2}{3}-\frac {5}{18}) ×36$
$=\frac {1}{2} ×36+\frac {2}{3} ×36-\frac {5}{18} ×36$
$=18+24-10$
$=32$
$=15 ×\frac {9}{8}+15 ×\frac {7}{8}$
$=15 ×(\frac {9}{8}+\frac {7}{8})$
$=15 ×2$
$=30$
$\begin {aligned}解:x&=\frac {3}{14}×\frac {7}{12}\\x &=\frac {1}{8}\end {aligned}$
$\begin {aligned}解:\frac {1}{2}x&=2\\x &=4\end {aligned}$
$\begin {aligned}解:\frac {5}{7}x&=\frac {7}{8}×\frac {5}{14}\\\frac {5}{7}x&=\frac {5}{16}\\x &=\frac {7}{16}\end {aligned}$
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