第130页 - 学习与评价七年级数学苏科版江苏凤凰教育出版社

4或5

$解：原式=\ 2\frac{1}2+2.5+1-1\frac{1}2$

$\ \ \ \ \ \ \ \ =\ 5+1-1.5$

$\ \ \ \ \ \ \ \ =4.5$

$解：原式=-3×4-(-6)²$

$\ \ \ \ \ \ \ \ =-12-36$

$\ \ \ \ \ \ \ \ =-48$

解：原式=18+32÷(-8)-16×5

=18+(-4)-80

=14-80

=-66

$解：原式=-12-12÷\ [\frac{2}3×(-64)×\frac{3}2-(-4)]$

$\ \ \ \ \ \ \ \ =-12-12÷\ [(\frac{2}3×\frac{3}2)×(-64)+4]$

$\ \ \ \ \ \ \ \ =-12-12÷(-64+4)$

$\ \ \ \ \ \ \ \ =-12-12÷(-60)$

$\ \ \ \ \ \ \ \ =-12-\ (-\frac{1}5)$

$\ \ \ \ \ \ \ \ =-12+\ \frac{1}5$

$\ \ \ \ \ \ \ \ =\ -11\frac{4}5$

$解：原式=-35+90$

$\ \ \ \ \ \ \ \ =55$

$ 解：原式= (1+\frac{2}3-\frac{3}4)×(-12)$

$ \ \ \ \ \ \ \ \ = 1×(-12)+\frac{2}3×(-12)-\frac {3}4×(-12)$

$ \ \ \ \ \ \ \ \ = -12-8-(-9)$

$ \ \ \ \ \ \ \ \ =-20+9$

$ \ \ \ \ \ \ \ \ =-11\ $

$解:-4＜-3\frac{1}{4}＜-2＜0＜1.5＜\frac{7}{2}.$