$解:根据题意,易得AN=4m,AD=0.8m,BN=7.2m,BF= 1.6m.$
$∵MN⊥NQ,AC⊥NQ,$
$∴ MN//AC.\ $
$∴ △CAD∽MND.$
$∴\frac{CA}{MN}=\frac{AD}{ND}$
$∴MN=\frac{CA×ND}{AD}=\frac{1.6×(4+0.8)}{0.8}=9.6(\mathrm {m}).$
$同理,可得△EBF∽△MNF.$
$∴\frac{EB}{MN}=\frac{BF}{NF}$
$∴ EB=\frac{BF.MN}{NF}=\frac{1.6×9.6}{7.2+1.6}≈1.75(\mathrm {m}).\ $
$∴ 小军的身高BE约为1.75m$