$证明:(1)\because CE∥AB,$
$\therefore \angle E=\angle EAB,\angle B=\angle ECB,$
$\therefore \triangle CED∽\triangle BAD,$
$\therefore \frac {CE}{AB}=\frac {CD}{BD},$
$\because \angle E=\angle EAB,\angle EAB=\angle CAD,$
$\therefore \angle E=\angle CAD,$
$\therefore CE=CA,$
$\therefore \frac {AB}{AC}=\frac {BD}{CD}.$
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