电子课本网 第62页

第62页

信息发布者:
$\frac{2}{5}$
$\frac{1}{3}$
1
$\frac{2}{9}$
$\frac{12}{35}$
$\frac{1}{3}$
$​\begin{aligned} 解: x&=\frac 12-\frac 14\\x&=\frac 14\end{aligned}​$
$​\begin{aligned} 解: x&=1-\frac 35\\x&=\frac 25\end{aligned}​$
$​\begin{aligned} 解: x&=\frac 56+\frac 12\\x&=\frac 43\end{aligned}​$
$​\begin{aligned} 解: x&=\frac 25+\frac 47\\x&=\frac {34}{35}\end{aligned}​$
​$ =\frac {7}{8}+\frac {1}{8}+\frac {4}{7}$​
​$=1+\frac {4}{7}$​
​$=\frac {11}{7}$​
​$ =\frac {9}{5}-(\frac {2}{7}+\frac {5}{7})$​
​$=\frac {9}{5}-1$​
​$=\frac {4}{5}$​
​$ =(\frac {5}{9}+\frac {4}{9})-(\frac {3}{8}+\frac {3}{8})$​
​$=1-\frac {6}{8}$​
​$=\frac {1}{4}$​