电子课本网 第67页

第67页

信息发布者:
$ \begin{aligned}&=\frac{15}{24}-\frac4{24}+\frac{16}{24} \\ &=\frac98 \\ \end{aligned}$
$ \begin{aligned}&=2-(\frac{12}{15}-\frac{10}{15}) \\ &=1\frac{13}{15} \\ \end{aligned}$
$ \begin{aligned}&=\frac{22}{24}-(\frac4{24}+\frac3{24}) \\ &=\frac58 \\ \end{aligned}$
$ \begin{aligned}&=\frac{14}{18}+\frac{15}{18}-\frac6{18} \\ &=\frac{23}{18} \\ \end{aligned}$
3
7
$\frac {47}{28}$
4
9
$\frac{19} {20}-\frac{1} {8}+\frac{19} {20} = \frac{71} {40}(吨)$
$答:这堆货物原有\frac {71}{40}吨。$
1
3
$\frac{4} {7}+\frac{4} {7}+\frac{2} {9} = \frac{86} {63}(米)$
$答:这个等腰三角形的周长是\frac {86}{63}米。$
$1−\frac{3} {8}-\frac{3} {8}=\frac{1} {4}\ $
$答:运往甲市的货物占了这堆货物的\frac {1}{4}。$