电子课本网 第110页

第110页

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$=\frac {11}{15}-\frac {1}{6}-\frac {8}{15}$
$=\frac {3}{15}-\frac {1}{6}$
$=\frac {1}{30}$
$=\frac {16}{18}-\frac {3}{18}+\frac {12}{18}$
$=\frac {25}{18}$
$=\frac {13}{9}-\frac {2}{5}-\frac {4}{9}$
$=1-\frac {2}{5}$
$=\frac {3}{5}$
$=\frac {7}{8}+\frac {1}{8}+\frac {7}{12}$
$=1+\frac {7}{12}$
$=1\frac {7}{12}$
$=\frac {9}{12}-\frac {2}{12}+\frac {4}{12}$
$=\frac {11}{12}$
$=\frac {7}{9}-\frac {4}{7}+\frac {2}{9}$
$=(\frac {7}{9}+\frac {2}{9})-\frac {4}{7}$
$=1-\frac {4}{7}$
$=\frac {3}{7}$
$=\frac {5}{3}-(\frac {2}{7}+\frac {5}{7})$
$=\frac {5}{3}-1$
$=\frac {2}{3}$
$=\frac {7}{5}-\frac {7}{9}-\frac {2}{5}+\frac {7}{9}$
$=(\frac {7}{5}-\frac {2}{5})+(\frac {7}{9}-\frac {7}{9})$
$=1-0$
$=1$
$=\frac {3}{8}+\frac {1}{16}+\frac {1}{32}+\frac {1}{64}+\frac {1}{128}+\frac {1}{256}$
$=1-\frac {1}{2}-\frac {1}{256}$
$=\frac {127}{256}$
$=(1000-\frac {1}{9})+(100-\frac {1}{9})+(10-\frac {1}{9})+\frac {1}{3}$
$=(1000+100+10)+(\frac {1}{9}+\frac {1}{9}+\frac {1}{9}-\frac {1}{3})$
$=1110$
$ \begin{aligned}解:42+2x&=92 \\ 2x&=50 \\ x&=25 \\ \end{aligned}$
$ \begin{aligned}解:1.2x&=18 \\ 1.2x÷1.2&=18 \\ x&=15 \\ \end{aligned}$
$ \begin{aligned}解:5x&=10.8 \\ 5x÷5&=10.8÷5 \\ x&=2.16 \\ \end{aligned}$
$ \begin{aligned}解:4x-18&=32 \\ 4x&=50 \\ x&=12.5 \\ \end{aligned}$
$ \begin{aligned}解:x&=\frac {17}{18}-\frac {2}{9} \\ x&=\frac {13}{18} \\ \end{aligned}$
$ \begin{aligned}解:x&=\frac {1}{3}+\frac {1}{4} \\ x&=\frac {7}{12} \\ \end{aligned}$
$0.53a$
$8.1b$
$9.8x$
$16.3y$
$2x$
$3y$
$\frac {5}{9}$
1
$\frac {3}{8}$
$\frac {4}{9}$
$\frac {1}{10}$
$\frac {31}{20}$
$\frac {9}{8}$
$\frac {5}{7}$