$a$可能是$1,$$2,$$3,$$4,$$5,$$6$
$\frac 17=0.\dot {1}4285\dot {7},$$\frac 27=0.\dot {2}8571\dot {4}$
$\frac 37=0.\dot {4}2857\dot {1},$$\frac 47=0.\dot {5}7142\dot {8}$
$\frac 57=0.\dot {7}1428\dot {5},$$\frac 67=0.\dot {8}5714\dot {2}$
$9039÷(1+4+2+8+5+7)=334……21$
只有$\frac {6}{7}$化成循环小数后,$ 1$组循环节中
的前$4$位数字之和是$21$
答:$a$是$6。$