电子课本网 第10页

第10页

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$解:(1)ρ=\frac {m_样 }{V_样}=\frac {140\ \text {g}}{50\ \text {cm}^3}=2.8\ \text {g/cm}^3=2.8×10^{3}\ \text {kg/m}^3$
$(2)m_碑=ρV_碑=2.8×10^{3}\ \text {kg/m}^3× 30\ \text {m}^3=8.4×10^{4}\ \text {kg}$
$解:V_铁=\frac {m}{ρ_铁}=\frac {1.58\ \text {kg}}{7.9×10^{3}\ \text {kg/m}^3}=2×10^{-4}\ \text {m}^3=0.2\ \text {dm}^3$
$是空心的$
$V_空=V-V_铁=0.5\ \text {dm}^3-0.2\ \text {dm}^3=0.3\ \text {dm}^3$
$m_水=ρV=1.0×10^{3}\ \text {kg/m}^3×0.3×10^{-3}\ \text {m}^3=0.3\ \text {kg}$
$m_总=m+m_水=1.58\ \text {kg}+0.3\ \text {kg}=1.88\ \text {kg}$