电子课本网 第21页

第21页

信息发布者:
物体E
36
​​$ 解:V=\frac {m_水}{ρ_水}=\frac { (140-40) g}{1\ \text {g/cm}^3}=100\ \text {cm}^3$​​
​​$ ρ=\frac {m_油 }{V}=\frac { (120-40) g}{100\ \text {cm}^3}=0.8\ \text {g/cm}^3$​​
​​$ 解:V_铁=\frac {m_铁}{ρ_铁}=\frac { 79\ \text {g}}{7.9\ \text {g/cm}^3}=10\ \text {cm}^3$​​
​​$ 是空心的,V_空=V-V_铁=12\ \text {cm}^3-10\ \text {cm}^3=2\ \text {cm}^3$​​
​​$ m_水=ρ_水V_空=1\ \text {g/cm}^3×2\ \text {cm}^3= 2\ \text {g}$​​
​​$ m_总=m_铁+m_水=79\ \text {g}+2\ \text {g}=81\ \text {g}$​​