$~~~~ \underbrace{222···22}_{2000个2}×\underbrace{999···99}_{2000个9}$
$=\underbrace{222···22}_{2000个2}×(1\underbrace{000···00}_{2000个0}-1)$
$=\underbrace{222···22}_{2000个2}×1\underbrace{000···00}_{2000个0}-\underbrace{222···22}_{2000个2}$
$=\underbrace{222···2}_{1999个2}1\underbrace{77···7}_{1999个7}8$