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第65页

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$\frac{5}{8}=\frac{75}{120},\frac{3}{5}=\frac{72}{120},\frac{1}{3}=\frac{40}{120}$
$因为\frac{75}{120}\gt \frac{72}{120}\gt \frac{40}{120}$
$所以\frac{5}{8}\gt \frac{3}{5}\gt \frac{1}{3}$
$答:多进香蕉,因为香蕉的销量最高。$
$方法一:\frac{2}{5}=\frac{14}{35},\frac{4}{7}=\frac{20}{35} ,\frac{2}{5}<\frac{4}{7}\ $
$方法二:\frac{2}{5}<\frac{1}{2},\frac{1}{2}<\frac{4}{7}, \frac{2}{5}<\frac{4}{7}$
$方法三:\frac{2}{5}=\frac{4}{10},\frac{4}{10}<\frac{4}{7} ,\frac{2}{5}<\frac{4}{7}\ $
$方法四:\frac{2}{5}=0.4,\frac{4}{7}≈0.571,\frac{2}{5}<\frac{4}{7}$
A
D
B
$\frac{12}{19}>\frac{10}{17}>\frac{15}{26}>\frac{6}{11}$
37
$\frac{a}{11}<\frac{7}{b}$
$即\frac{ab}{11b}<\frac{77}{11b}$
$可见ab最大为 76,a与b的和最大为1+76=77$
$答:a与b的和最大为77。$
(更多请点击查看作业精灵详解)
(更多请点击查看作业精灵详解)
(更多请点击查看作业精灵详解)
$\frac{5}{6}和\frac{3}{18}$
$\frac{5}{6}=\frac{15}{18}$
$\frac{5}{6}>\frac{13}{18}$

$\frac{10}{11}和\frac{11}{12}$
$ \begin{aligned} \frac{10}{11}&=\frac{120}{132} \\ \frac{11}{12}&=\frac{121}{132} \\ \end{aligned}$
$\frac{120}{132}\lt \frac{121}{132}$
$\frac{10}{11}<\frac{11}{12}$

$\frac{3}{8}和\frac{7}{12}$
$ \begin{aligned} \frac{3}{8}&=\frac{9}{24} \\ \frac{7}{12}&=\frac{14}{24} \\ \end{aligned}$
$\frac{9}{24}\lt \frac{14}{24}$
$\frac{3}{8}<\frac{7}{12}$

$\frac{3}{14}和\frac{2}{21}$
$ \begin{aligned} \frac{3}{14}&=\frac{9}{42} \\ \frac{2}{21}&=\frac{4}{42} \\ \end{aligned}$
$\frac{9}{42}\gt \frac{4}{42}$
$\frac{3}{14}\gt \frac{2}{21}$
$ \begin{aligned}1-\frac{2022}{2023}&=\frac{1}{2023} \\ 1-\frac{2023}{2024}&=\frac{1}{2024} \\ \end{aligned}$
$因为\frac{1}{2023}> \frac{1}{2024}$
$所以\frac{2022}{2023}\lt \frac{2023}{2024}$
$\frac{1}{3}=\frac{11111}{33333}=\frac{33333}{99999}$
$因为\frac{11110}{33333}\lt \frac{11111}{33333}$
$\frac{33333}{99999}\lt \frac{33333}{99998}$
$所以\frac{11110}{33333}\lt \frac{33333}{99998}$
$由题意的\frac{1}{4}<\frac{17}{()}<\frac{13}{50}$
$因为1、17、13的最小公倍数是221$
$所以把三个分子统一成221$
$ \begin{aligned}这样\frac{1}{4}&=\frac{221}{884} \\ \frac{13}{50}&=\frac{221}{850} \\ \frac{17}{()}&=\frac{221}{()×13} \\ \end{aligned}$
$由此可知( )×13应该在850和884之间(不包含850和884)$
$所以括号里可填66或67,共2个。$