电子课本网 第31页

第31页

信息发布者:
$\frac{1}{4}$
$\frac{29}{28}$
$\frac{11}{24}$
$\frac{1}{2}$
$\frac{5}{18}$
$\frac{5}{36}$
$\frac{5}{6}$
$\frac{2}{3}$
$ \begin{aligned}解:x&=\frac {2}{3}-\frac {1}{9} \\ x&=\frac {5}{9} \\ \end{aligned}$
$ \begin{aligned} 解:x&=\frac {5}{6}+\frac {5}{8} \\ x&=\frac {35}{24} \\ \end{aligned}$
$ \begin{aligned} 解:5x&=\frac {3}{8}+\frac {5}{8} \\ 5x&=1 \\ x&=\frac {1}{5} \\ \end{aligned}$
$ \begin{aligned} 解:x+\frac {1}{5}&=\frac {2}{3} \\ x&=\frac {7}{15} \\ \end{aligned}$
$​=\frac {7}{8}+\frac {6}{8}+\frac {1}{3}​$
$​=\frac {13}{8}+\frac {1}{3}$
$​​=\frac {47}{24}​$
$​=\frac {5}{6}-\frac {8}{15}​​$
$=\frac {3}{10}​$
$​=5-(\frac {5}{11}+\frac {17}{11})​​$
$=5-2$
$​​=3​$
$​=(\frac {23}{15}+\frac {7}{15})-(\frac {7}{12}+\frac {5}{12})​​$
$=2-1​​$
$=1​$
$​=\frac {10}{21}+\frac {11}{21}-1​​$
$=1-1​​$
$=0​$
$​=(\frac {2}{3}+\frac {1}{3})-(\frac{5}{12}+\frac {7}{12})​​$
$=1-1​​$
$=0​$