解:$(4)$原式$= \frac {30×(\frac 13x-0.2y)}{30×(\frac {1}{2} x+0.3y)}=\frac {10x-6y}{15x+9y}$
$(5)$原式$= \frac {30×(\frac {1}{3} x- \frac {1}{5} y)}{30×(2x+\frac 16y)}=\frac {10x-6y}{60x+5y}$
$(6)$原式$=\frac {100×(\frac {1}{100} x^2- \frac {1}{5} )}{100×(1.3x^2+0.24)}=\frac {x^2-20}{130x^2+24}$