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第3页

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$解：原式=-\frac {2z}{3y}$

$解：原式=-\frac {4}{3}a^6y^2$

$解：原式=\frac {c}{7ab}$

$解：原式=-\frac {1}{(x-y)^2}$

$解：原式=\frac {1}{b-a}$

$解：原式=-\frac {3}{4c}$

$ \begin{aligned}解：原式&=\frac {m(a+b-c)}{a+b-c} \\ &=m \\ \end{aligned}$

$ \begin{aligned} 解：原式&=\frac {a-b}{(a+b)(a-b)} \\ &=\frac{1}{a+b} \\ \end{aligned}$

$ \begin{aligned}解：原式&=\frac {a(a+b)}{b(a+b)} \\ &=\frac {a}b \\ \end{aligned}$

$ \begin{aligned}解：原式&=\frac {(a-2b)^2}{(a+2b)(a-2b)} \\ &=\frac {a-2b}{a+2b} \\ \end{aligned}$

$ \begin{aligned}解：原式&=\frac {(a+b)^2}{(a+b)(a-b)} \\ &=\frac {a+b}{a-b} \\ \end{aligned}$

$解：原式=\frac {(x+3)(x-3)}{2(3-x)}$

$=- \frac {x+3}{2}$

$ \begin{aligned} 解：原式&=\frac {(x+1)(x-1)}{x(1-x)} \\ &=-\frac {x+1}{x} \\ \end{aligned}$

$ \begin{aligned}解：原式&=\frac {a(a^2-4b^2)}{2a(a^2-4ab+4b^2)} \\ &=\frac {a(a+2b)(a-2b)}{2a(a-2b)^2} \\ &=\frac {a+2b}{2(a-2b)} \\ \end{aligned}$

$ \begin{aligned}解：原式&=\frac {(x+3)(x-3)}{2(3-x)} \\ &=-\frac {x+3}2 \\ \end{aligned}$