解:$G_{基石}=m_{基石}\ \mathrm {g}=ρVg=ρShg$
$ p=\frac {G_{碑}+G_{基石}}S=\frac {G_{碑}+ρShg}S=\frac {G_{碑}}S+ρgh$
$ S=\frac {G_{碑}}{p-ρgh}=\frac {10^6\ \mathrm {N}}{7×10^4\ \mathrm {Pa}-2×10^3\ \mathrm {kg/m}^3×10\ \mathrm {N/kg}×1\ \mathrm {m}}=20\ \mathrm {m^2}$