解:设小明骑自行车的速度为$x\ \mathrm {km/}\mathrm {\ \mathrm {min}},$小亮骑自行车的速度为$y\ \mathrm {km/}\mathrm {\ \mathrm {min}},$
根据题意,得$\begin{cases}{30x+30y=11}\\{(22+20)x+20y=11}\end{cases},$
解得$\begin{cases}{x=\dfrac {1}{6}}\\{y=\dfrac {1}{5}}\end{cases}$
∴小明骑自行车的速度为$\frac {1}{6}\ \mathrm {km/}\mathrm {\ \mathrm {min}},$小亮骑自行车的速度为$\frac {1}{5}\ \mathrm {km/}\mathrm {\ \mathrm {min}}.$