$解:(2)∵∠ADC=∠AEB=90°$
$∴∠BDC=∠CEB=90°$
$在△DOB和 △EOC中$
$\begin{cases}{∠BDO=∠CEO}\\{∠DOB=∠EOC}\\{OB=OC}\end{cases}$
$∴△DOB≌△EOC(\mathrm {AAS})$
$∴OD=OE$
$在Rt△ADO和Rt△AEO中$
$\begin{cases}{OD=OE}\\{OA=OA}\end{cases}$
$∴Rt△ADO≌Rt△AEO(\mathrm {HL})$
$∴∠1=∠2$