$解：原式 =(1+3+5+7+9+11+13+15+$
$17)+(\frac{1}{6}+\frac{1}{12}+\frac{1}{20}+\frac{1}{30}+\frac{1}{42}+\frac{1}{56}+\frac{1}{72}+\frac{1}{90})$
$=81+(\frac{1}{2}-\frac{1}{3}+\frac{1}{3}-\frac{1}{4}+\frac{1}{4}-\frac{1}{5}+\frac{1}{5}-\frac{1}{6}+\frac{1}{6}-$
$\frac{1}{7}+\frac{1}{7}-\frac{1}{8}+\frac{1}{8}-\frac{1}{9}+\frac{1}{9}-\frac{1}{10})$
$=81+(\frac{1}{2}-\frac{1}{10})$
$= 81+\frac{2}{5}$
$=81 \frac{2}{5} .$
