电子课本网 第76页

第76页

信息发布者:
C
B
C
D
​$6x²y²$​
​$2x(x+1)(x-1)$​
​$10a²b²c$​
​$2a²$​
​$5bc$​
​$ab²$​
​$\frac {x+1}{x^2-1}$​
​$\frac {x-1}{x^2-1}$​
​$\frac 1{x^2-1}$​
 解:​$\frac {2}{xy}=\frac {4}{2xy}$​,​$\frac {x}{2y}=\frac {x^2}{2xy}$​
解:​$\frac {5}{-4ab^2}=-\frac {25a}{20a^2b^2}$​,​$\frac {4}{5a^2b}=\frac {16b}{20a^2b^2}$​
解:​$\frac {x}{a(x-y)}=\frac {bx}{ab(x-y)}$​,​$\frac {y}{b(y-x)}= -\frac {ay}{ab(x-y)}$​
解:​$\frac {a}{(x-y)^2}= \frac {a(x+y)}{(x-y)^2(x+y)}$​,
​$\frac {b}{(x-y)(x+y)}=\frac {b(x-y)}{(x-y)^2(x+y)}$​