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C
B
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D
$6x²y²$
$2x(x+1)(x-1)$
$10a²b²c$
$2a²$
$5bc$
$ab²$
$\frac {x+1}{x^2-1}$
$\frac {x-1}{x^2-1}$
$\frac 1{x^2-1}$
解:$\frac {2}{xy}=\frac {4}{2xy}$,$\frac {x}{2y}=\frac {x^2}{2xy}$
解:$\frac {5}{-4ab^2}=-\frac {25a}{20a^2b^2}$,$\frac {4}{5a^2b}=\frac {16b}{20a^2b^2}$
解:$\frac {x}{a(x-y)}=\frac {bx}{ab(x-y)}$,$\frac {y}{b(y-x)}= -\frac {ay}{ab(x-y)}$
解:$\frac {a}{(x-y)^2}= \frac {a(x+y)}{(x-y)^2(x+y)}$,
$\frac {b}{(x-y)(x+y)}=\frac {b(x-y)}{(x-y)^2(x+y)}$
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