第16页 - 通城学典课时作业本七年级数学苏科版江苏专用

C

①③④

$解得：原式=64x^6$

$ \begin{aligned}解:原式&={x}^{3(2+m)}÷{x}^{2m} \\ &={x}^{6+3m-2m} \\ &={x}^{m+6} \\ \end{aligned}$

$ \begin{aligned}解:原式&={(q-p)}^{4-3+2} \\ &=(q-p)³ \\ \end{aligned}$

$ \begin{aligned}解：原式&=4a^6b^2-3a^6b^2 \\ &=a^6b^2 \\ \end{aligned}$

$解：原式=a³×{b}^{3×2}+(-\frac {1}{8})a³{b}^6=\frac {7}{8}a³{b}^6$

$当a=\frac {1}{4}，b=4时，原式=\frac {7}{8}×(\frac {1}{4})³×{4}^6=56$

C

$ \begin{aligned} 解:原式&=8-\frac{1}{16}-8÷1 \\ &=8-\frac{1}{16}-8 \\ &=-\frac{1}{16} \\ \end{aligned}$

$ \begin{aligned}解:原式&={(-\frac {2}{3})}^{201}×{1.5}^{201}×1.5-\frac {1}{8}+81\ \\ &={(-\frac {2}{3}×1.5)}^{201}×1.5-\frac {1}{8}+81\ \\ &=-1.5-\frac {1}{8}+81\ \\ &=79\frac {3}{8} \\ \end{aligned}$