$解:(1)∵( \sqrt{75})²=75,$ $8²=64,75＞64,$ $∴ \sqrt{75}＞8$
$解:(2)∵(− \sqrt{11})²=11,$ $(−3)²=9,11＞9,$ $∴− \sqrt{11}＜−3$
$解:(3)∵\sqrt{2})²=2,$ $1.42²=2.0164,$ $2＜2.0164,$ $∴ \sqrt{2}＜1.42$
$解:(4)∵( \sqrt{12})²=12,$ $4²=16,12＜16,$ $∴ \sqrt{12}＜4.$ $∴ \sqrt{12}−1＜3$
$解:(1)∵1-\sqrt{2}−(1−\sqrt{3})$ $=\sqrt{3}−\sqrt{2}＞0,$ $∴1−\sqrt{2}＞1−\sqrt{3}$
$解:(2)\frac{\sqrt{3}−1}{5}- \frac{1}{5}=\frac{\sqrt{3}−2}{5}$ $∵ \sqrt{3}＜2,$ $∴\frac{\sqrt{3}−2}{5}＜0.$ $∴\frac{\sqrt{3}−1}{5}＜\frac{1}{5}$
$解:(3)\frac{\sqrt{7}−2}{2}−(\sqrt{17}−3)$ $=2−\frac{\sqrt{7}}{2}$ $=\frac{4−\sqrt{7}}{2}.$ $∵ 4＞ \sqrt{7},$ $∴\frac{4−\sqrt{7}}{2}＞0.$ $∴\frac{\sqrt{7}−2}{2}−(\sqrt{7}−3)＞0.$ $∴\frac{\sqrt{7}−2}{2}＞\sqrt{7}−3$
$解:(4)\frac{\sqrt{24}}{2}−1−1.5$ $=\frac{\sqrt{24}−5}{2}.$ $∵ \sqrt{24}＜5,$ $∴ \frac{\sqrt{24}−5}{2}＜0.$ $∴\frac{\sqrt{24}}{2}−1＜1.5$
$解:A:−π,B:−\sqrt{3},C:0,D:0.3,E:\sqrt{2},F:3.14,G:\frac{7}{2}$ $−π＜-\sqrt{3}＜0＜0.3＜ \sqrt{2}＜3.14＜\frac{7}{2}$
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