解:$(2) $∵$(\frac {5}{4})^3=\frac {125}{64},$$(\frac {4}{5})^{-3}=\frac {125}{64}$
∴$(\frac {5}{4})^3=(\frac {4}{5})^{-3} $
$(4) $原式$ =(\frac {15}{7})^3 ×(\frac {7}{5})^4$
$=(\frac {15}{7})^3 ×(\frac {7}{5})^3 ×\frac {7}{5}$
$=(\frac {15}{7} ×\frac {7}{5})^3 ×\frac {7}{5}$
$=27 ×\frac {7}{5}$
$=\frac {189}{5}$