电子课本网 第48页

第48页

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​$解:由题意可得\ \left\{\begin{array}{l}2 x+5 y=-6 \\ 3 x-5 y=16\end{array}\right. ,解得:\ \left\{\begin{array}{l}x=2 \\ y=-2\end{array}\right. ,$​
​$将\ \left\{\begin{array}{l}x=2 \\ y=-2\end{array}\right.\ 分别代入a x-b y=-4 ,b x+a y=-8 \text { 中得 }\left\{\begin{array}{l}2a+2b=-4 \\2b-2a=-8\end{array}\right. \text {, }$​
​$解得:\ \left\{\begin{array}{l}a=1 \\ b=-3\end{array}\right. ,$​
​$则(2a+b)^{2024}=(2 \times 1-3)^{2024} =(-1)^{2024}=1.$​
解:把​$\begin{cases}{x=-3, }\\{y=-1 代入方程 ②, 得 4 × (-3)=b ·(-1)-2 , 解得 b=10 .}\end{cases}$​
把​$\begin{cases}{x=5, }\\{y=4代入方程 ①, 得 5\ \mathrm {a}+5 ×4=15 , 解得 a=-1 .}\end{cases}$​
所以​$ a^{2024}+(-\frac {b}{10})^{2023}=(-1)^{2024}+(-\frac {10}{10})^{2023}= 1+(-1)=0 .$​