解：$\begin{cases}3(x - 1)\lt 4 + 2x,①\\\frac{x - 9}{5}\lt 2x,②\end{cases}$
解不等式①：
$\begin{aligned}3(x - 1)&\lt 4 + 2x\\3x-3&\lt 4 + 2x\\3x-2x&\lt 4 + 3\\x&\lt 7\end{aligned}$
解不等式②：
$\begin{aligned}\frac{x - 9}{5}&\lt 2x\\x - 9&\lt 10x\\x-10x&\lt 9\\-9x&\lt 9\\x&\gt - 1\end{aligned}$
所以原不等式组的解集为$-1\lt x\lt 7。$
