解：连接$OA.$$\because CD$为$\odot O$的直径，$AB\perp CD，$$AB = 1$尺$ = 10$寸，$\therefore AE=\frac{1}{2}AB = 5$寸.设$OA = x$寸，则$OE=(x - 1)$寸.在$Rt\triangle AEO$中，由勾股定理，得$x^{2}=5^{2}+(x - 1)^{2}，$
展开式子得$x^{2}=25+x^{2}-2x + 1，$
移项可得$2x=26，$
解得$x = 13.$$\therefore CD = 2OA = 26$寸.
